5.6 Optimization Problemsap Calculus



Graphical Meaning Functions in 2 variables can be graphed in 3 dimensions: At each point on this graph, there is a slope; unlike calculus in 2 dimensions the slope is.

Math 105- Calculus for Economics & Business Sections 10.3 & 10.4: Optimization problems How to solve an optimization problem? Step 1: Understand the problem and underline what is important ( what is known, what is unknown, what we are looking for, dots) 2. Step 2: Draw a “diagram”; if it is possible. Week 5 of the Course is devoted to the extension of the constrained optimization problem to the. N-dimensional space. This week students will grasp how to apply bordered Hessian concept to classification of critical points arising in different constrained optimization problems.

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5.6 Optimization Problemsap Calculus 2nd Edition

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Section 4-8 : Optimization

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5.6 Optimization Problemsap Calculus Solver

  1. Find two positive numbers whose sum is 300 and whose product is a maximum. Solution
  2. Find two positive numbers whose product is 750 and for which the sum of one and 10 times the other is a minimum. Solution
  3. Let (x) and (y) be two positive numbers such that (x + 2y = 50) and (left( {x + 1} right)left( {y + 2} right)) is a maximum. Solution
  4. We are going to fence in a rectangular field. If we look at the field from above the cost of the vertical sides are $10/ft, the cost of the bottom is $2/ft and the cost of the top is $7/ft. If we have $700 determine the dimensions of the field that will maximize the enclosed area. Solution
  5. We have 45 m2 of material to build a box with a square base and no top. Determine the dimensions of the box that will maximize the enclosed volume. Solution
  6. We want to build a box whose base length is 6 times the base width and the box will enclose 20 in3. The cost of the material of the sides is $3/in2 and the cost of the top and bottom is $15/in2. Determine the dimensions of the box that will minimize the cost. Solution
  7. We want to construct a cylindrical can with a bottom but no top that will have a volume of 30 cm3. Determine the dimensions of the can that will minimize the amount of material needed to construct the can. Solution
  8. We have a piece of cardboard that is 50 cm by 20 cm and we are going to cut out the corners and fold up the sides to form a box. Determine the height of the box that will give a maximum volume. Solution




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